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50 lines
1.5 KiB
Python
Executable File
50 lines
1.5 KiB
Python
Executable File
#!/usr/bin/env python3
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# xorcheck.py - find xor values for 8-bit LRC
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#
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# Adam Laurie <adam@algroup.co.uk>
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# http://rfidiot.org/
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#
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# This code is copyright (c) Adam Laurie, 2009, All rights reserved.
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# For non-commercial use only, the following terms apply - for all other
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# uses, please contact the author:
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#
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# This code is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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#
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# This code is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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import sys
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import os
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if(len(sys.argv) < 3):
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print("""
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\t{0} - Generate final byte for XOR LRC
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Usage: {0} <ID Byte1> <ID Byte2> ... <LRC>
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\tSpecifying the bytes of a UID with a known LRC will find the last byte value
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\tneeded to generate that LRC with a rolling XOR. All bytes should be specified in HEX.
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Example:
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\t{0} 04 00 80 64 ba
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Should produce the output:
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\tTarget (BA) requires final LRC XOR byte value: 5A\n""".format(sys.argv[0]))
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os._exit(True)
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target= int(sys.argv[len(sys.argv) - 1],16)
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lrc= 0x00
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for i in range(len(sys.argv) - 1):
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lrc ^= int(sys.argv[i + 1],16)
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print('\nTarget (%02X) requires final LRC XOR byte value: %02X\n' % (target,lrc))
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